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Additional Exercises

Cycloalkanes are named based on the number of C atoms in them, just like regular alkanes, but with the prefix cyclo– on the name. What are the names of the three smallest cycloalkanes?
Cycloalkenes are named similarly to cycloalkanes (see Exercise 1). What are the names of the cycloalkenes with five, six, and seven C atoms?
Draw the bond-line structure of all noncyclic alkanes with only four C atoms.
Draw the bond-line structure of all noncyclic alkanes with only five C atoms.
Cyclic alkanes can also have substituent groups on the ring. Draw the bond-line structure of all cyclic alkanes with only four C atoms.
Cyclic alkanes can also have substituent groups on the ring. Draw the bond-line structure of all cyclic alkanes with only five C atoms.
Draw and name all possible isomers of pentene.
Draw and name all possible normal (that is, straight-chain) isomers of heptyne.
Polyunsaturated alkenes have more than one C–C double bond. Draw the carbon backbone of all possible noncyclic polyunsaturated alkenes with four C atoms and two double bonds. What are the complete molecular formulas for each possible molecule?
Draw the carbon backbone of all possible five-carbon cyclic alkenes with two double bonds, assuming no substituents on the ring.
If a hydrocarbon is combined with enough halogen, all the H atoms will eventually be substituted with that halogen atom. Write the balanced chemical reaction between ethane and excess chlorine.
If a hydrocarbon is combined with enough halogen, all the H atoms will eventually be substituted with that halogen atom. Write the balanced chemical reaction between butane and excess bromine.
Molecules with multiple double bonds can also participate in addition reactions. Draw the structure of the product when butadiene, CH₂=CH–CH=CH₂, reacts with chlorine.
Draw the structure of the product when allene, CH₂=C=CH₂, reacts with bromine.
What is the maximum number of methyl groups that can be on a propane backbone before the molecule cannot be named as a propane compound?
Explain why cycloethane cannot exist as a real molecule.
In the gasoline industry, what is called isooctane is actually 2,2,4-trimethylpentane. Draw the structure of isooctane.
Isooctane (see Exercise 17) is an isomer of what straight-chain alkane?
The actual name for the explosive TNT is 2,4,6-trinitrotoluene. If the structure of TNT is as shown below, propose the structure of the parent compound toluene.
$\chemfig{-[:-90]*6(-(-O_2N)=-(-NO_2)=-(-NO_2)=)}$
Phenol is hydroxybenzene, the simplest aromatic alcohol. Picric acid is an explosive derivative of phenol whose formal name is 2,4,6-trinitrophenol. With reference to Exercise 19, draw the structure of picric acid.
Draw the structures of all possible straight-chain isomers of bromopentane.
Draw the structures of all the possible isomers of butanol. Include branched isomers.
What is the final product of the double elimination of HCl from 1,1-dichloroethane?
Draw the structure of the final product of the double elimination of 1,3-dibromopropane.
Draw the structure of and name the alcohol whose double elimination would yield the same product as in Exercise 23. Name the molecule as a hydroxyl-substituted compound.
Draw the structure of and name the alcohol whose double elimination would yield the same product as in Exercise 24. Name the molecule as a hydroxyl-substituted compound.
Draw the smallest molecule that can have a separate aldehyde and carboxylic acid group.
Name the functional group(s) in the following structure:
$\chemfig{*6(-=(*5(-(--[:0]NH_2)--(=O)-))-=-(-HO)=)}$
Ethyl acetate is a common ingredient in nail-polish remover because it is a good solvent. Draw the structure of ethyl acetate.
A lactone is an ester that has its ester functional group in a ring. Draw the structure of the smallest possible lactone. (It is called acetolactone, which might give you a hint about its structure.)
Draw the structure of diethyl ether, once used as an anaesthetic.
The smallest cyclic ether is called an epoxide. Draw its structure.
Write the chemical reaction of HCl with trimethylamine.
Putrescine and cadaverine are molecules with two amine groups on the opposite ends of a butane backbone and a pentane backbone, respectively. They are both emitted by rotting corpses. Draw their structures and determine their molecular formulas.
With four monomers, draw two possible structures of a copolymer composed of ethylene and propylene.
With four monomers, draw two possible structures of a copolymer composed of ethylene and styrene.
Draw the silicone that can be made from this monomer:
$\chemfig{[:90]*6((-[:-90]Si?[a]-[:-90])-----(-[:-90]Si?[a,2]-[:-90]([:-60]*6(-----))))}$
One of the ingredients in the original Silly Putty was a silicone polymer with two methyl groups on each Si atom. Draw this silicone.

Answers

cyclopropane, cyclobutane, and cyclopentane

Bond-line structure of all noncyclic alkanes with only four C atoms:
$\chemfig{-[:-30]-[:30]-[:-30]}\hspace{4em}\chemfig{-[:-90](-[:-150])-[:-30]}$

Bond-line structure of all cyclic alkanes with only four C atoms:
$\chemfig{*4(----)}\hspace{4em}\chemfig{*3(-(-)--)}$

Isomers of pentene:
$\begin{align*} \chemfig{=[:30]-[:-30]-[:30]-[:-30]}&\hspace{4em}\chemfig{-[:30]=[:-30]-[:30]-[:-30]} \\ \\ \chemfig{=[:30](-[:90])-[:-30]-[:30]}&\hspace{4em}\chemfig{-[:30](-[:90])=[:-30]-[:30]} \end{align*}$

Carbon backbone of all possible noncyclic polyunsaturated alkenes with four C atoms and two double bonds:
$\chemfig{H_2C=C=CH-[:-60]CH_3}\hspace{4em}\chemfig{H_2C=[:-60]HC-CH=[:-60]CH_2}$
Both molecular formulas are C₄H₆.

C₂H₆ + 6Cl₂ → C₂Cl₆ + 6HCl

Structure of butadiene’s reaction with chlorine:
$\chemfig{H-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-(-[:90]Cl)(-[:-90]H)-H}$

Structure of isooctane:
$\chemfig{-[:30](-[:90])(-[:150])-[:-30](-[:-90])-[:30]-[:-30]}$

Structure of toluene:
$\chemfig{-[:-90]*6(-=-=-=)}$

Straight-chain isomers of bromopentane:
$\chemfig{Br-[:30]-[:-30]-[:30]-[:-30]-[:30]}\hspace{4em}\chemfig{-[:30](-[:90]Br)-[:-30]-[:30]-[:-30]}\hspace{4em}\chemfig{-[:-30]-[:30](-[:90]Br)-[:-30]-[:30]}$

ethyne
$\begin{align*}\chemfig{HO-[:-60]--[:60]OH} &\hspace{2em} \chemfig{HO-[:-60](-[:-120]HO)-}\end{align*}$

The names are 1,2-dihydroxyethane and 1,1-dihydroxyethane, respectively.

$\chemfig{H-[:-30](=[:-90]O)-[:30](=[:90]O)-[:-30]OH}$

$\chemfig{-[:30](=[:90]O)-[:-30]O-[:30]-[:-30]}$

$\chemfig{-[:30]-[:-30]O-[:30]-[:-30]}$

(CH₃)₃N + HCl → (CH₃)₃NHCl

(answers will vary)
$\begin{array}{c}\chemfig{-[@{left,0.5}]C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-[@{right,0.5}]} \polymerdelim[delimiters={[]},height=25 pt]{left}{right} \\ \\ \chemfig{-[@{left,0.5}]C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H_2)-C(-[:90]H)(-[:-90]CH_3)-C(-[:90]H_2)-[@{right,0.5}]} \polymerdelim[delimiters={[]},height=25 pt]{left}{right} \end{array}$

$\chemfig{-[@{left,0.5}]Si(-[:90])(-[:-90]([:-60]*6(-----)))-Si(-[:90]([:120]*6(-----)))(-[:-90])-[:0, 2.0]Si(-[:90])(-[:-90]([:-60]*6(-----)))-Si(-[:90]([:120]*6(-----)))(-[:-90])-[@{right,0.5}]} \polymerdelim[delimiters={[]},height=20 pt]{left}{right}$

Chapter 17. Kinetics

Chemistry

Notes

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