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Organic Chemistry I: 3.3 pKa of Organic Acids and Application of pKa to Predict Acid-Base Reaction Outcome

Organic Chemistry I
3.3 pKa of Organic Acids and Application of pKa to Predict Acid-Base Reaction Outcome
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table of contents
  1. Cover
  2. Title Page
  3. Copyright
  4. Table Of Contents
  5. Introduction
  6. Acknowledgements
  7. Chapter 1 Basic Concepts in Chemical Bonding and Organic Molecules
    1. 1.1 Chemical Bonding
    2. 1.2 Lewis Structure
    3. 1.3 Resonance Structures
    4. 1.4 Resonance structures in Organic Chemistry
    5. 1.5 Valence-Shell Electron-Pair Repulsion Theory (VSEPR)
    6. 1.6 Valence Bond Theory and Hybridization
    7. Answers to Practice Questions Chapter 1
  8. Chapter 2 Fundamental of Organic Structures
    1. 2.1 Structures of Alkenes
    2. 2.2 Nomenclature of Alkanes
    3. 2.3 Functional Groups
    4. 2.4 IUPAC Naming of Organic Compounds with Functional Groups
    5. 2.5 Degree of Unsaturation/Index of Hydrogen Deficiency
    6. 2.6 Intermolecular Force and Physical Properties of Organic Compounds
    7. Answers to Practice Questions Chapter 2
  9. Chapter 3 Acids and Bases: Organic Reaction Mechanism Introduction
    1. 3.1 Review of Acids and Bases and Ka
    2. 3.2 Organic Acids and Bases and Organic Reaction Mechanism
    3. 3.3 pKa of Organic Acids and Application of pKa to Predict Acid-Base Reaction Outcome
    4. 3.4 Structural Effects on Acidity and Basicity
    5. 3.5 Lewis Acids and Lewis Bases
    6. Answers to Practice Questions Chapter 3
  10. Chapter 4 Conformations of Alkanes and Cycloalkanes
    1. 4.1 Conformation Analysis of Alkanes
    2. 4.2 Cycloalkanes and Their Relative Stabilities
    3. 4.3 Conformation Analysis of Cyclohexane
    4. 4.4 Substituted Cyclohexanes
    5. Answers to Practice Questions Chapter 4
  11. Chapter 5 Stereochemistry
    1. 5.1 Summary of Isomers
    2. 5.2 Geometric Isomers and E/Z Naming System
    3. 5.3 Chirality and R/S Naming System
    4. 5.4 Optical Activity
    5. 5.5 Fisher Projection
    6. 5.6 Compounds with More Than One Chirality Centers
    7. Answers to Practice Questions Chapter 5
  12. Chapter 6 Structural Identification of Organic Compounds: IR and NMR Spectroscopy
    1. 6.1 Electromagnetic Radiation and Molecular Spectroscopy
    2. 6.2 Infrared (IR) Spectroscopy Theory
    3. 6.3 IR Spectrum and Characteristic Absorption Bands
    4. 6.4 IR Spectrum Interpretation Practice
    5. 6.5 NMR Theory and Experiment
    6. 6.6 ¹H NMR Spectra and Interpretation (Part I)
    7. 6.7 ¹H NMR Spectra and Interpretation (Part II)
    8. 6.8 ¹³C NMR Spectroscopy
    9. 6.9 Structure Determination Practice
    10. Answers to Practice Questions Chapter 6
  13. Chapter 7 Nucleophilic Substitution Reactions
    1. 7.1 Nucleophilic Substitution Reaction Overview
    2. 7.2 SN2 Reaction Mechanism, Energy Diagram and Stereochemistry
    3. 7.3 Other Factors that Affect SN2 Reactions
    4. 7.4 SN1 Reaction Mechanism, Energy Diagram and Stereochemistry
    5. 7.5 SN1 vs SN2
    6. 7.6 Extra Topics on Nucleophilic Substitution Reaction
    7. Answers to Practice Questions Chapter 7
  14. Chapter 8 Elimination Reactions
    1. 8.1 E2 Reaction
    2. 8.2 E1 Reaction
    3. 8.3 E1/E2 Summary
    4. 8.4 Comparison and Competition Between SN1, SN2, E1 and E2
    5. Answers to Practice Questions Chapter 8
  15. Chapter 9 Free Radical Substitution Reaction of Alkanes
    1. 9.1 Homolytic and Heterolytic Cleavage
    2. 9.2 Halogenation Reaction of Alkanes
    3. 9.3 Stability of Alkyl Radicals
    4. 9.4 Chlorination vs Bromination
    5. 9.5 Stereochemistry for Halogenation of Alkanes
    6. 9.6 Synthesis of Target Molecules: Introduction of Retrosynthetic Analysis
    7. Answers to Practice Questions Chapter 9
  16. Chapter 10 Alkenes and Alkynes
    1. 10.1 Synthesis of Alkenes
    2. 10.2 Reactions of Alkenes: Addition of Hydrogen Halide to Alkenes
    3. 10.3 Reactions of Alkenes: Addition of Water (or Alcohol) to Alkenes
    4. 10.4 Reactions of Alkenes: Addition of Bromine and Chlorine to Alkenes
    5. 10.5 Reaction of Alkenes: Hydrogenation
    6. 10.6 Two Other Hydration Reactions of Alkenes
    7. 10.7 Oxidation Reactions of Alkenes
    8. 10.8 Alkynes
    9. Answers to Practice Questions Chapter 10
  17. About the Author

3.3 pKa of Organic Acids and Application of pKa to Predict Acid-Base Reaction Outcome

As we mentioned before, all organic compounds could be acids, because they all have hydrogen atoms that could potentially be donated. Most organic acids are weak acids with a small Ka. For example, acetic acid CH3COOH has a Ka of 1.8×10-5. Lots of other organic acids are even weaker than acetic acid, and it is this weak acidity that makes it difficult to realize that some organic compounds are actually acids.

However, this weak acidity is very important in Organic Chemistry. Since it is not that very convenient to say or to remember Ka values like 1.8×10-5, pKa is used more often in Organic Chemistry to refer to the relative acidity of different acids. The definition of pKa is:

pKa = -logKa

The smaller the pKa value, the larger the Ka, and the stronger the acidity is.

The pKa of most organic acids range between 5~60. While it is impossible to know the pKa of every organic compound, it is very useful to understand the pKa (and acidity) based on the functional groups involved, because the same functional groups usually have similar pKas. The approximate ranges of pKa values for seven major functional groups are listed in Table 3.1, which serves as a very valuable starting point for us to predict and understand the acidity of any organic molecule. The strongest organic acid listed here is carboxylic acid, with a pKa of about 5; the weakest organic acids are the alkanes with pKa values of over 50. Since approximate ranges of pKa values are listed in the table, the exact pKa value of a group varies for different compounds because of the structural differences. Fortunately however, it is usually not necessary to know the exact pKa values for most cases in organic chemistry, and the approximate range is good enough.

Carboxylic acid (~5), Alcohol (~16), Aldehyde (~16-~20), Alkyne (~25), Amine (~35-40) (NH3~38), Alkene (~45), Alkane (>50)
Table 3.1: Approximate ranges of pKa values for common organic functional groups

Notes for the pKa values in Table 3.1:

  • Acidity is the ability of a compound to donate H+, so when we talk about the acidity (Ka and pKa) of an organic compound, it must be about a specific H atom (highlighted blue in the table). For different H atoms in the same compound, the acidity and  pKa are different. As for the example of methanol:
The acidity of CH3OH therefore usually refer to the H in OH group, the more acidic hydrogen
Figure 3.3a Methanol
  • It is very useful to memorize the approximate ranges of pKa listed in Table 3.1.
  • The acidity of the functional groups in the table decreases from top to the bottom, and the basicity of the conjugate bases in the last column increases from top to bottom, because the stronger the acid, the weaker the conjugate base is.

Predict the Outcome of Organic Acid-Base Reaction — Use pKa as Criterion

With the knowledge of acidity and pKa, we are now ready to see how to apply this information to the understanding of organic reactions from an acid-base perspective.

The following reaction is an example in Section 3.2. If you take a closer look at the reactants and products, you will find that the “product” side also contains an acid (ammonia NH3), and a base (methoxide CH3O–). Now the question is, how can we be so sure that the reaction proceeds to the “product” side as written? The question can also be asked in a different way: if equilibrium is established for the reaction mixture, which side will the position of the equilibrium predominantly favour? Left or right?

CH3OH (acid) + NH2 (base) = CH3O (conjugate base) + NH3 (conjugate acid)
Figure 3.3b Acid-Base Reaction

To answer that question, we will learn about a general rule for acid-base reaction: Acid-base reactions always favour the formation of the weaker acid and the weaker base. This is because the equilibrium always favours the formation of more stable products, and weaker acids and bases are more stable than stronger ones.

HA (stronger acid) + B (stronger base) [smaller pKa] = A- (weaker base) + HB+ (weaker acid) [larger pKa]
Figure 3.3c Smaller pKa and larger pKa

With pKa values available at hand, the relative acidity of reactants vs products can be compared by comparing their pKa values, and the reaction will proceed to the side of the acid with a larger pKa (larger pKa means smaller Ka, therefore weaker acid).

So for this reaction, the pKa check indicates that ammonia NH3 is a weaker acid than methanol CH3OH,  so the reaction does proceed to the right side with CH3O– and NH3 as the major products.

CH3OH (pKa~15, smaller pKa, stronger acid) + NH2 (stronger base) = CH3O (weaker base) + NH3 (pKa~35-40, larger pKa, weaker acid)
Figure 3.3d Which direction does the reaction go?

Notes: Only comparing between acids is good enough for this purpose, because if CH3OH is stronger than NH3, then the conjugate base CH3O– must be weaker than the other base NH2–.

Examples

Show the products of the following reactions and predict the predominant side of the equilibrium.

Reaction 1

C2H2 + NH2 (N has two lone pairs and a negative charge) =

Reaction 2

C2H2 + OH (O has a negative charge) =

Solutions:

Reaction 1

equilibrium favors the products right side of the reaction

Reaction2

the equilibrium favors the reactants left side of the reaction

Are there any practical applications for such a prediction? Yes! Let’s compare the two reactions in the exercises above. Reaction 1 indicates that if ethyne (HC≡CH) and amide (NH2–) are mixed together, the reaction does proceed to the products side, meaning HC≡CH could be deprotonated by amide NH2–. However, if HC≡CH and hydroxide OH– are mixed together as shown in reaction 2, no reaction occurs, or we can say that HC≡CH can not be deprotonated by OH– because OH– is not strong enough! So if you are working in the lab and have the option of choosing between NH2– or OH– to deprotonate HC≡CH, you now know which one to choose. 

The idea that OH– is not a strong enough base may bother you a lot, since it conflicts with the “common knowledge” that we learned in General Chemistry, where OH– is a strong base. Generally speaking, OH– is a pretty strong base; however, it is just barely not strong enough to deprotonate HC≡CH, which is a very weak acid, with a pKa of about ~25. Since HC≡CH is much weaker than the “weak acids” we learned in General Chemistry, a much stronger base, like NH2–, is required to deprotonate it.

Annotate

Next Chapter
3.4 Structural Effects on Acidity and Basicity
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Chemistry
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